5014x^2+58x-30=1

Solution for 5014x^2+58x-30=1 equation:

5014x^2+58x-30=1

We move all terms to the left:

5014x^2+58x-30-(1)=0

We add all the numbers together, and all the variables

5014x^2+58x-31=0

a = 5014; b = 58; c = -31;
Δ = b2-4ac
Δ = 582-4·5014·(-31)
Δ = 625100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{625100}=\sqrt{100*6251}=\sqrt{100}*\sqrt{6251}=10\sqrt{6251}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(58)-10\sqrt{6251}}{2*5014}=\frac{-58-10\sqrt{6251}}{10028}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(58)+10\sqrt{6251}}{2*5014}=\frac{-58+10\sqrt{6251}}{10028}
$